Submitted by Ok_Kareem_7223 t3_10qviic in askscience
Background: I know some fishermen who do this, because it melts some of the ice, and the resulting liquid in there is as cold as the ice, and it quickly freezes the fish placed in the cooler.
These same fishermen claim that the resulting slurry stays cold much LONGER than just a cooler of ice without the salt. They've done no experiments with timing it, they just make the claim.
I understand the salt melting the ice, and the resulting slurry being partially liquid and the liquid being as cold as the solid. What I don't understand, or even BELIEVE, without some explanation is that he mass would stay cool LONGER in one form or another. It's as if they're saying that by adding salt, they've removed even more energy (heat) from the mass.
Sounds wrong to me. Am I missing something?
Appaulingly t1_j6u8o9s wrote
Ice in equilibrium with (pure) water will stay at 0 degrees C. No higher and no lower. If you add salt to the water, the equilibrium temperature will decrease. So a brine ice mixture can be lowered below 0 degrees C. This lower temperature system would "stay cool longer" because it is colder.
>It's as if they're saying that by adding salt, they've removed even more energy (heat) from the mass
Melting is an endothermic process. This process will "remove" heat via bond breaking in the ice. So by adding salt to the water and lowering the equilibrium temperature, the system will respond by melting some of the ice. This consumes energy and lowers the temperature until equilibrium temperature is reached.
EDIT: To clarify a misconception, an observed decrease in temperature does not equate to the "removal of energy from the system" (when simply adding salt). A decrease in temperature can occur when there is a transfer of kinetic energy to potential (when ice melts endothermically). Regardless, in the water-ice system the temperature is not actually proportional to kinetic energy. That is only the case in an ideal gas.